Question

@phi @SolomonZelman @Zarkon @ribhu

http://prntscr.com/68kzex

Answer 1

when x is equal to -4, to find the h(x) when x=-4 , you simply plug in -4 instead of x into the function h(x).

Answer 2

So when x=-4, what will your h(x) be ?

Answer 3

what is 4 times x +1 ?

Answer 4

you want to go in terms of an arithmetic sequence, phi ? :)

Answer 5

I think they want to show that h(x) has "instructions" on how to get a number
put in x, and "get out" h(x)

hopefully rachella can make sense of that ?

Answer 6

well... yes.

So, Rachella, we are evaluating the function h(x) at some (suggested in your table) values of x.

When we evaluate the function h(x) at x=-4 (for instance)
YOu plug in -4 for x into the function h(x).

Like this, \(\large\color{slate}{ h(x)=4x+1 }\)
\(\large\color{slate}{ h(\color{red}{-4})=4(\color{red}{-4})+1 }\)
\(\large\color{slate}{ h(\color{red}{-4})=-16+1 }\)
\(\large\color{slate}{ h(\color{red}{-4})=\color{blue}{-15} }\)


where do you put this?
\(\normalsize\color{ black }{\LARGE{\bbox[5pt, ,border:2px solid white ]{ \huge{ \begin{array}{| l | c | r |}
\hline \scr~~~x~~ & \scr h(x) \\
\hline
\scr~~~-4~ & \scr ~\color{blue}{-15}~~ \\
\hline
\scr~~~-3~ & \scr \\
\hline
\scr~~~~0~ & \scr \\
\hline
\scr~~~~1~ & \scr \\
\hline
\scr~~~~4~ & \scr \\
\hline \end{array} }}}}\)

Answer 7

plug in -3 and other values of x (that are in the table) into the function h(x) (just the same way as I did with -4) and complete the table.

Answer 8

if something isn't clear, ask...