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Mathematics 9 Online
OpenStudy (mary.rojas):

Forgot how to do these,can someone help please :)

OpenStudy (solomonzelman):

what did you forget ?

OpenStudy (mary.rojas):

these >.<

OpenStudy (bibby):

\(log_x(a)=b\implies x^b=a\)

OpenStudy (mary.rojas):

Yea... x^3=(1/8)

OpenStudy (mary.rojas):

Idk how to get the same base? ermm or whatever it's called

OpenStudy (solomonzelman):

perfect, but adding that \(\large\color{black}{ \displaystyle a>0 }\)

OpenStudy (solomonzelman):

\(\large\color{black}{ \displaystyle 1/8=1/(2^3)=2^{-3} }\)

OpenStudy (mary.rojas):

...You think you could show me this using another problem...like instead of 1/8,use 1/27??

OpenStudy (mary.rojas):

tbh,it's not clicking what to do

OpenStudy (bibby):

27=3^3

OpenStudy (mary.rojas):

x^3=3^-3...then?

OpenStudy (bibby):

in your case, \(x^3=\dfrac{1}{27}\\x^3=\dfrac{1}{3^{3}}\\x=\dfrac{1}{3}\)

OpenStudy (mary.rojas):

ohh thanks guys :) so my other problem would be 1/2

OpenStudy (bibby):

for reference, \(\dfrac{\sqrt{x}}{\sqrt y}=\sqrt{\dfrac{x}{y}}\)

OpenStudy (bibby):

yea

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