Question

Forgot how to do these,can someone help please :)

Answer 1

what did you forget ?

Answer 2

these >.<

Answer 3

\(log_x(a)=b\implies x^b=a\)

Answer 4

Yea...
x^3=(1/8)

Answer 5

Idk how to get the same base? ermm or whatever it's called

Answer 6

perfect, but adding that \(\large\color{black}{ \displaystyle a>0 }\)

Answer 7

\(\large\color{black}{ \displaystyle 1/8=1/(2^3)=2^{-3} }\)

Answer 8

...You think you could show me this using another problem...like instead of 1/8,use 1/27??

Answer 9

tbh,it's not clicking what to do

Answer 10

27=3^3

Answer 11

x^3=3^-3...then?

Answer 12

in your case, \(x^3=\dfrac{1}{27}\\x^3=\dfrac{1}{3^{3}}\\x=\dfrac{1}{3}\)

Answer 13

ohh thanks guys :)
so my other problem would be 1/2

Answer 14

for reference, \(\dfrac{\sqrt{x}}{\sqrt y}=\sqrt{\dfrac{x}{y}}\)

Answer 15

yea