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Factor completely: x^5 + x^4 -13x^3 -13x^2 + 36x - 36 My answer: (x^2) (x-2) (7^2-5) (-7^2 - 5x) (x-3) (x+3)
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@triciaal
one approach is to group each set of 2 terms and factor
now factor out the common term of (x + 1)
use substitution to factor the quadratic
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factors of -36 that add up to -13 are -9 and -4 sign problem should that be -36x -36 in the original?
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