Question

I really need help. I didn't pay attention in class and I need someone to teach me this here. Please help.

Answer 1

Triangle ABC is similar to triangle PQR:

Two similar triangles ABC and PQR are shown. Triangle ABC has sides AB = c, BC = a, and AC = b. Triangle PQR has sides PQ = r, QR = p, and PR = q. Angle CAB is congruent to angle RPQ. Angle ABC is congruent to angle RQP. Angle ACB is congruent to angle QRP.

Which equation is correct?

c by a is equal to q by r
c by r is equal to a by b

c by q is equal to a by r

Answer 2

image coming up...

Answer 3

http://learn.flvs.net/webdav/assessment_images/educator_geometry_v14/pool_Geom_3641_0300_Subtest_04_12/image0014e1c83ed.jpg

Answer 4

please help me.

Answer 5

c over a = q over r
c over r = a over b
c over r = a over p
c over q= a over r

I really need help. I didn't pay attention in class and I need someone to teach me this here. Please help.

Answer 6

c over r = a over p
since corresponding angles are equal, ratios of corresponding sides should be equal

Answer 7

Thank you, but I was wanting to know how to do it than to just give me an awnser. But still, thanks!

Answer 8

It's scaling. For example, draw triangle, then multiply length of each side by 2, to illustrate, and build new triangle with compass, then you'll get similar triangles and their corresponding angles will be equal as in your case. and ratios of corresponding sides will be equal. "Play" with integers, it helps.

Answer 9

@Sputnikcer

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