Question

Given two terms from a geometric sequence, identify the first term and the common ratio:

Answer 1

\[a _{5}=48 .... a _{11} = 3072\]

Answer 2

Hey!

Answer 3

A. \[a _{1} =2 ......... r=3\]

Answer 4

B. \[a _{1}=2 ...... r=2\]

Answer 5

C. \[a _{1}=3 ...... r=3\]

Answer 6

D. \[a _{1}=3....... r=2\]

Answer 7

@Michele_Laino

Answer 8

@Michele_Laino

Answer 9

Hey I got 15 questions and I need your help if you will help me I'll medal you each time ok!

Answer 10

please us this formula:
\[{a_{11}} = {a_1}{q^{10}}\]
where q is the common ratio

Answer 11

and this one:
\[{a_5} = {a_1}{q^4}\]

Answer 12

if I divide side bu side those above formulas, I get:
\[\frac{{{a_{11}}}}{{{a_5}}} = {q^6}\]
now substitute your data, and you will get the value for q

Answer 13

oops...side by side...

Answer 14

what do you get?

Answer 15

Ok, I gotcha and I got B.

Answer 16

hint:
\[\frac{{{a_{11}}}}{{{a_5}}} = \frac{{3072}}{{48}} = 64\]

Answer 17

ok but thats not an answer

Answer 18

am i supposed to combine that some how

Answer 19

please your common ratio q is:
\[64 = {q^6}\]
so
\[\begin{gathered}
q = 2 \hfill \\
and\;\qquad\\
{a_1} = \frac{{{a_5}}}{{{q^4}}} = \frac{{48}}{{16}} = ...? \hfill \\
\end{gathered} \]

Answer 20

ohhh so 3

Answer 21

yes!

Answer 22

because of 6 and 2

Answer 23

ok i gotcha

Answer 24

so r =3

Answer 25

and a1 equals 3 so C.

Answer 26

I think q=r = 2
since 64= 2^6

Answer 27

kk d next question

Answer 28

so your answer is option D.