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(x2/3) / (x4/9)
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\[x \frac{ 2 }{ 3 } / x \frac{ 4 }{ 9 }\]
do u on ur calc!
howww
hint:\[\huge\rm \frac{ x^n }{ x^m } = x^{n-m}\]
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if the question is \[\frac{x^{\frac{2}{3}}}{x^{\frac{4}{9}}}\] use the rule @Nnesha has stated
\[\huge\rm \frac{ x^\frac{ 2 }{ 3 } }{ x^\frac{ 4 }{ 9 }}\] this is your question right ?? bec both base are same at the numerator and at the den. so you can move bottom exponent at the top ;D like in that example i gave you
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