Can someone please help me through this radical expressions problem?

Question

quickstudent · Answer

(√5x) - x = 0
(√5x) - x + x = 0 + x
(√5x) = 0 + x
√5x)^2 = (0 + x)^2
5x = (0 + x)(0 + x)
5x = 0^2 + 0x + 0x + x^2
5x = x^2
5x/5 = x^2/5
x = 

This was how far I was able to get, but I need help to finish it.

quickstudent · Answer

@campbell_st @mathstudent55

campbell_st · Answer

ok... just to check is 

$$\sqrt{5x} - x = 0$$

campbell_st · Answer

and are you solving for x..?

quickstudent · Answer

Yes

quickstudent · Answer

I don't know how to go further than this.

campbell_st · Answer

well can't you add x to both sides

$$\sqrt{5x} = x$$

now square both sides

$$5x = x^2$$

then you can have 

$$x^2 - 5x = 0$$

factor and 

$$x(x - 5) = 0$$

so perhaps you can find the solutions from here.

quickstudent · Answer

OK, let me try it a moment.