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Mathematics 15 Online
OpenStudy (anonymous):

Medal I need help with using the pythagorean theorem with 3d figures please ill add in the attachments

OpenStudy (anonymous):

OpenStudy (anonymous):

brb

OpenStudy (matt101):

The slant height is the hypotenuse of the right triangle indicated. The length of the base of the triangle is equal to the radius of the cone, which is half the diameter (questions 1 and 2), or half the length of the base of the pyramid (question 3). Question 4 you'll need to solve in 2 steps. First you'll need to find the length of the diagonal across a square FACE of the cube. You can do this by considering the diagonal as the hypotenuse of a triangle formed by two of that face's sides. This diagonal then becomes the base of your second triangle, and the height is just the side length of the cube. Using these two pieces of information you can find the length of the yellow diagonal indicated in the figure. Question 5 follows the same procedure, just make sure you don't mix up what side you're using to solve since now we have a rectangular prism instead of a cube.

OpenStudy (anonymous):

? english pls. @matt101

OpenStudy (matt101):

What didn't you get?

OpenStudy (anonymous):

the part were EVERYTHING can you work the problems out on the draw pad and i will do the next step.

OpenStudy (anonymous):

@matt101

OpenStudy (anonymous):

|dw:1424809976859:dw|

OpenStudy (matt101):

Hmm ok

OpenStudy (matt101):

I have a meeting in less than 10 mins so I can't walk you through this right now...but maybe later on? Unless someone else jumps in before then lol

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