Question

(7 √2 -3 √3) (4√6+3√12)

Answer 1

those symbols are supposed to be radicals... can anyone read that?

Answer 2

Your problem:
\[\left(7 \sqrt{2} - 3 \sqrt{3}\right) \times \left(4 \sqrt{6} + 3 \sqrt{12}\right)\]

To solve this, you have to FOIL (acronym for First Outer Inner Last)
Using a general expression
\[\left(A + B\right) \times \left(C + D\right)\]
FOIL is done like this:
\[AC + AD + BC + BD \]

Answer 3

so its broken down like..... 28 rad12 + 21 rad24 -12 rad 18 -9 rad 36?

Answer 4

Yep, that's right! Now just combine the terms. Keep in mind that some radicals can be simplified further. As an example, \(\sqrt{18} = \sqrt{9 \times 2} = 3 \sqrt{2}\)

Answer 5

thank you so much! that makes this so much easier!

Answer 6

No problem! Happy studying!