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Mathematics 7 Online
OpenStudy (anonymous):

What is the equation of the graphed linear model? y = x + http://static.k12.com/calms_media/media/1549000_1549500/1549109/2/a4d8cb5972366f402912ed1759aeadaa5560d1f1/MS_IMC-141014-181213.jpg

OpenStudy (anonymous):

@iGreen

OpenStudy (igreen):

Take the two points on the line and plug them into slope-formula. (1, 3) and (9, 11) \(m = \dfrac{y_2-y_1}{x_2-x_1}\) \(m = \dfrac{11-3}{9-1}\) Simplify

OpenStudy (anonymous):

\[\frac{ 8 }{ 8 } = 1\]

OpenStudy (igreen):

Yes, so the slope is 1. Now we can plug this into point-slope form along with one of the two points. \(y - y_1 = m(x - x_1)\) Where \(y_1\) is the y-value of the point, \(x_1\) is the x-value of the point, and \(m\) is the slope. So we have: \(y - 3 = 1(x - 1)\) Distribute 1 into the parenthesis: \(y - 3 = x - 1\) Add 3 to both sides, what's -1 + 3?

OpenStudy (anonymous):

2?

OpenStudy (igreen):

Yep, so we have: \(y = x + 2\)

OpenStudy (igreen):

So you can put 1 in the first blank and 2 in the 2nd.

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