x^2+14x+38 / x+8????? Please help!!!
factor quadratic equation x^2 + 14 x+38 find two number if you multiply them you should get 38 andif you add or subtract them you should get 14
btw that's not factorable so you have to use quadratic formula hmmm
it is not factor-able, since the discriminant is not a perfect square. \(\large\color{slate}{ (14)^2-(4)(1)(38) }\) \(\large\color{slate}{ 44 }\)
undefined the answer is x^2+14x +38/x+8
But you can make it, \(\large\color{black}{ \displaystyle \frac{ x^2+14x+38 }{x+8} }\) \(\large\color{black}{ \displaystyle \frac{ x^2+14x+48-10 }{x+8} }\) \(\large\color{black}{ \displaystyle \frac{ x^2+14x+48 }{x+8} -\frac{ 10 }{x+8} }\)
that is for polynomial division, if you don't like setting it in long or synthetic division.
Or, do you want to solve for x? then shouldn't it be equal to something?
divide..........long division or synthetic divison
or the way I did
(I didn't finish it of course)
for me?
lol
Nope.
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