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OpenStudy (anonymous):
x^2+14x+38 / x+8????? Please help!!!
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Nnesha (nnesha):
factor quadratic equation x^2 + 14 x+38
find two number if you multiply them you should get 38
andif you add or subtract them you should get 14
Nnesha (nnesha):
btw that's not factorable so you have to use quadratic formula
hmmm
OpenStudy (solomonzelman):
it is not factor-able, since the discriminant is not a perfect square.
\(\large\color{slate}{ (14)^2-(4)(1)(38) }\)
\(\large\color{slate}{ 44 }\)
OpenStudy (anonymous):
undefined the answer is x^2+14x +38/x+8
OpenStudy (solomonzelman):
But you can make it, \(\large\color{black}{ \displaystyle \frac{ x^2+14x+38 }{x+8} }\)
\(\large\color{black}{ \displaystyle \frac{ x^2+14x+48-10 }{x+8} }\)
\(\large\color{black}{ \displaystyle \frac{ x^2+14x+48 }{x+8} -\frac{ 10 }{x+8} }\)
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OpenStudy (solomonzelman):
that is for polynomial division, if you don't like setting it in long or synthetic division.
OpenStudy (solomonzelman):
Or, do you want to solve for x?
then shouldn't it be equal to something?
Nnesha (nnesha):
divide..........long division or synthetic divison
OpenStudy (solomonzelman):
or the way I did
OpenStudy (solomonzelman):
(I didn't finish it of course)
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OpenStudy (solomonzelman):
for me?
OpenStudy (solomonzelman):
lol
Nnesha (nnesha):
Nope.
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