Ask your own question, for FREE!
Mathematics 7 Online
OpenStudy (awkwardpanda):

Jana hit a golf ball with an initial velocity of 102 ft per second at an angle of 67 degrees with the horizontal. After 2 second how far had the ball traveled horizontally? (79.7ft)? after 3 seconds how far has the ball traveled vertically? (137.6ft)?

OpenStudy (anonymous):

@KyanTheDoodle

OpenStudy (anonymous):

You need to find the total time it stays in the air, which would be finding the vertical velocity and using the kinematic equations to solve for t somehow

OpenStudy (anonymous):

Oops just realized the time is given

OpenStudy (anonymous):

If that's the case then all you need to do is find the horizontal velocity and plug in the known variables in the kinematic equations

OpenStudy (awkwardpanda):

I thought i did that, so are my answers not correct?

OpenStudy (anonymous):

no their not

OpenStudy (awkwardpanda):

Can you show me how please?

OpenStudy (anonymous):

yea @juanjohnguy show us how

OpenStudy (anonymous):

Let me get the kinematic equations in front of me really quick

OpenStudy (awkwardpanda):

thank you

OpenStudy (anonymous):

Since we only care about the horizontal distance that the ball travels in the first one, we know that there is no horizontal acceleration and so we can use the constant velocity equation.....which is something like x=x(naught) +vt

OpenStudy (anonymous):

Which should give you the solution for the first question. It seems like I got the same answer as you did for the first one

OpenStudy (awkwardpanda):

So 79.7 is correct? at least i did something right lol. But i'm very unsure about the vertical one.

OpenStudy (anonymous):

The wording for the second quest is weird since its a little vague

OpenStudy (anonymous):

I would imagine you would need to use the the constant acceleration kinematic equations to solve this one

OpenStudy (awkwardpanda):

Half of these questions are pretty vague. How do i do that

OpenStudy (anonymous):

Let me do a little calculation and see where my numbers fall very quickly

OpenStudy (awkwardpanda):

okay thank you

OpenStudy (anonymous):

Ok so it looks like my answer is close to yours. The only thing I am not sure about is whether it is asking for the height the ball is at at 3 seconds, or the distance that the ball travels, which would include the vertical distance going up to the peak when it's velocity is zero and it reaches its max height + the little distance it goes when it falls back down

OpenStudy (anonymous):

I say that because I calculated that it reaches it's max height at about 2.915 seconds

OpenStudy (anonymous):

But the quest is asking for when t = 3 seconds

OpenStudy (anonymous):

and in the 0.085 extra seconds, the ball falls downward from it's max height, thus I am not sure if you need to add the distance it travels when it falls

OpenStudy (anonymous):

|dw:1424940403135:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!