Jana hit a golf ball with an initial velocity of 102 ft per second at an angle of 67 degrees with the horizontal. After 2 second how far had the ball traveled horizontally? (79.7ft)? after 3 seconds how far has the ball traveled vertically? (137.6ft)?
@KyanTheDoodle
You need to find the total time it stays in the air, which would be finding the vertical velocity and using the kinematic equations to solve for t somehow
Oops just realized the time is given
If that's the case then all you need to do is find the horizontal velocity and plug in the known variables in the kinematic equations
I thought i did that, so are my answers not correct?
no their not
Can you show me how please?
yea @juanjohnguy show us how
Let me get the kinematic equations in front of me really quick
thank you
Since we only care about the horizontal distance that the ball travels in the first one, we know that there is no horizontal acceleration and so we can use the constant velocity equation.....which is something like x=x(naught) +vt
Which should give you the solution for the first question. It seems like I got the same answer as you did for the first one
So 79.7 is correct? at least i did something right lol. But i'm very unsure about the vertical one.
The wording for the second quest is weird since its a little vague
I would imagine you would need to use the the constant acceleration kinematic equations to solve this one
Half of these questions are pretty vague. How do i do that
Let me do a little calculation and see where my numbers fall very quickly
okay thank you
Ok so it looks like my answer is close to yours. The only thing I am not sure about is whether it is asking for the height the ball is at at 3 seconds, or the distance that the ball travels, which would include the vertical distance going up to the peak when it's velocity is zero and it reaches its max height + the little distance it goes when it falls back down
I say that because I calculated that it reaches it's max height at about 2.915 seconds
But the quest is asking for when t = 3 seconds
and in the 0.085 extra seconds, the ball falls downward from it's max height, thus I am not sure if you need to add the distance it travels when it falls
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