Question

Find m angle T

Answer 1

HI!! (again)
identical to the last one, only the numbers are different

Answer 2

yea i know but i have a problem with these so can you just write it out for me and i ccan solve it myself ?

Answer 3

we can use the same wolfram link i sent the last time, just change the numbers in it

Answer 4

so would it be 22^2 + 12^2 + 19^2

Answer 5

but you might have to take a test or quiz on this in class so maybe we do it slowly
will you have to do that?

Answer 6

no hold on

Answer 7

the numerator is
\[\huge b^2+c^2\color{red}-a^2\]

Answer 8

so you have to properly identify \(a\)
it is the side opposite the angle

Answer 9

try again

Answer 10

wait so it would be: arccos((22^2+12^2-19^2)/(22*12*19))

Answer 11

not quite

Answer 12

what is the side OPPOSITE angle T

Answer 13

12?

Answer 14

yes
so your numerator was wrong

Answer 15

also the denominator is \(2bc\) not \(abc\)

Answer 16

try again, i bet you get it this time

Answer 17

so arccos((22^2+12^2-19^2)/(2*12*19)) ?

Answer 18

hmm still confused about the opposite side?

Answer 19

it is 12, not 19

Answer 20

arccos((22^2+19^2-12^2)/(2*12*19)) ok i think i got it?

Answer 21

almost !

Answer 22

the denominator does not have the side opposite the angle in it, it is the other two sides, the adjacent sides

Answer 23

so replace that 12 in the denominator by the 22, and you will have it

Answer 24

i am not trying to torture you, just trying to make sure you can get it on your own
i will write the answer if you want me to

Answer 25

arccos((22^2+19^2-12^2)/(2*22*19))

Answer 26

YES!!

Answer 27

ok so the answer would be 33.02 degrees ?

Answer 28

let me check

Answer 29

yuup

Answer 30

ok thanks again ur alot of help!

Answer 31

yw \[\color\magenta\heartsuit\]

Answer 32

if you have another one and want me to check the answer for you i can