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Mathematics 15 Online
OpenStudy (anonymous):

suppose a population of 50 crickets doubles in size every 4 months. How many crickets will be after 5 years?

OpenStudy (anonymous):

@eta

OpenStudy (7thgrader):

no need to fear some random guy is here

OpenStudy (anonymous):

7th grader, talking to whom?

OpenStudy (7thgrader):

@Help10questionsplease please let me do this one

OpenStudy (7thgrader):

guys i wanna do this one

OpenStudy (anonymous):

Sure, go ahead.. :)

OpenStudy (anonymous):

@7thGrader okay?

OpenStudy (7thgrader):

thank you so much!

OpenStudy (7thgrader):

i got this one sec

OpenStudy (7thgrader):

Ok so then 5x12 is 60 so divide 60 into 4

OpenStudy (7thgrader):

We should know: 1 year = 12 months Given: Doubles every 4 months So: 4 * 3 =12 Therefore: 1 year, there is 3 sets of 4 months. Hence: 4 * 3 = 12 Then: 2 years have 6 sets of 4 months. 3 years have 9 sets of 4 months 4 years have 12 sets of 4 months 5 years have 15 sets of 4 months Good so far?

OpenStudy (anonymous):

Okay o-o

OpenStudy (7thgrader):

We start with a population of 50 crickets So then: 50×2n 50×215 whats 2^15? after u get that, multiply what you got from that by 50. Try it and let me see what you get. :)

OpenStudy (7thgrader):

wait

OpenStudy (7thgrader):

50 X 2^15 is 1638400 there is your answer

OpenStudy (7thgrader):

medal?

OpenStudy (anonymous):

You are correct O.O

OpenStudy (7thgrader):

thanks!

OpenStudy (7thgrader):

YES I JUST GOT TO 50 SMART CENTS!

OpenStudy (anonymous):

XD thanks for helping

OpenStudy (7thgrader):

im 18 medals in math away from being a human calculator

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