suppose a population of 50 crickets doubles in size every 4 months. How many crickets will be after 5 years?
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OpenStudy (anonymous):
@eta
OpenStudy (7thgrader):
no need to fear some random guy is here
OpenStudy (anonymous):
7th grader, talking to whom?
OpenStudy (7thgrader):
@Help10questionsplease please let me do this one
OpenStudy (7thgrader):
guys i wanna do this one
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OpenStudy (anonymous):
Sure, go ahead.. :)
OpenStudy (anonymous):
@7thGrader okay?
OpenStudy (7thgrader):
thank you so much!
OpenStudy (7thgrader):
i got this one sec
OpenStudy (7thgrader):
Ok so then 5x12 is 60 so divide 60 into 4
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OpenStudy (7thgrader):
We should know:
1 year = 12 months
Given: Doubles every 4 months
So:
4 * 3 =12
Therefore:
1 year, there is 3 sets of 4 months. Hence: 4 * 3 = 12
Then:
2 years have 6 sets of 4 months.
3 years have 9 sets of 4 months
4 years have 12 sets of 4 months
5 years have 15 sets of 4 months
Good so far?
OpenStudy (anonymous):
Okay o-o
OpenStudy (7thgrader):
We start with a population of 50 crickets
So then:
50×2n
50×215
whats 2^15?
after u get that, multiply what you got from that by 50.
Try it and let me see what you get. :)
OpenStudy (7thgrader):
wait
OpenStudy (7thgrader):
50 X 2^15 is 1638400 there is your answer
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OpenStudy (7thgrader):
medal?
OpenStudy (anonymous):
You are correct O.O
OpenStudy (7thgrader):
thanks!
OpenStudy (7thgrader):
YES I JUST GOT TO 50 SMART CENTS!
OpenStudy (anonymous):
XD thanks for helping
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OpenStudy (7thgrader):
im 18 medals in math away from being a human calculator