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OpenStudy (anonymous):
@eta
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OpenStudy (anonymous):
OpenStudy (anonymous):
You must know that: \[1+ \tan^2(\theta) = \sec^2(\theta)\]
OpenStudy (anonymous):
is it 1 + tan or 1/tan
OpenStudy (anonymous):
i know that 1/cos(theta) = sec(theta) But I haven't seen it the way you just showed me
OpenStudy (anonymous):
you are doing the basics. I got it.. @SolomonZelman can you help him or her?
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OpenStudy (anonymous):
@mathstudent55
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