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Mathematics 20 Online
OpenStudy (anonymous):

ANYOND=E KNOW HOW TO SOLVE THIS?? if the nth term of a sequence is 2n+4 what is the sum of the first n terms

OpenStudy (anonymous):

@welshfella @Darknight200 @DarkBlueChocobo @whydoihavetosignup1 @diamondboy @Luigi0210 @EclipsedStar @Zarkon @DarkBlueChocobo @xX_GamerGirl_Xx @bibby @Nnesha

OpenStudy (anonymous):

@Somy @warpedkitten @Hero @ganeshie8 @mathmath333 @MathNinja_C

OpenStudy (mathmath333):

\(\large \color{black}{\begin{align} \sum_{i=1}^{N}(2n+4)\hspace{.33em}\\~\\ \implies 2\sum_{i=1}^{N}n+\sum_{i=1}^{N}4\hspace{.33em}\\~\\ \implies 2\dfrac{(N)(N+1)}{2}+4N\hspace{.33em}\\~\\ \implies (N^2+N)+4N\hspace{.33em}\\~\\ \implies N^2+5N\hspace{.33em}\\~\\ \end{align}}\)

OpenStudy (anonymous):

so do i put n^2+5n into the calculator @mathmath333

OpenStudy (mathmath333):

in the question formula for the sum of the first n terms of the nth term ( 2n+4) was asked which is this \(N^2+5N\)

OpenStudy (anonymous):

so that is the sum ? @mathmath333

OpenStudy (mathmath333):

yes the sum

OpenStudy (mathmath333):

Sum of first N terms

OpenStudy (anonymous):

thank you @mathmath333

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