Question

find the missing denominator for
7^16/7^12= 7^-18/?

Answer 1

Hey Bey :)
\[\Large\rm \frac{7^{16}}{7^{12}}=7^{\frac{-18}{x}}\]

Answer 2

Applying our exponent rule on the left side of the equation, subtracting the exponents,\[\Large\rm 7^{16-12}=7^{\frac{-18}{x}}\]

Answer 3

Now that the bases are the same, we can equate the exponents!\[\Large\rm 16-12=\frac{-18}{x}\]

Answer 4

And solve for x.

Answer 5

Or was the `?` supposed to be a denominator under the 7?
Maybe I misread that :p

Answer 6

Like this?\[\Large\rm \frac{7^{16}}{7^{12}}={\frac{7^{-18}}{x}}\]

Answer 7

the options are 7^-6, 7^-14, 7^-22,and 7^22 so I tried solving it and didn't see my answer

Answer 8

and yeah