Question

PLEASE HELP I WILL FAN AND MEDAL!!!!


Find a number that is between 8/11 and 0.85, 85 repeating.

A.157/198
B.88/99
C.23/33
D.39/66

Answer 1

Notice \(\dfrac{8}{11} = \color{blue}{\dfrac{72}{99}}\) and \(0.\overline{85} = \dfrac{85}{10^2-1} = \color{blue}{\dfrac{85}{99}}\)

Answer 2

right I figured that out for 0.85 but how did \[\frac{ 8 }{ 11 }\] become \[\frac{ 72 }{ 99 }\]

Answer 3

Multiply top and bottom of \(\frac{8}{11}\) by \(9\)

Answer 4

Oh okay I understand better now so what do i do next?

Answer 5

Even better, change the denominator of everything to \(198\) so that comparison becomes easy (99*2 = 198)

Answer 6

A.157/198 = `157/198`
B.88/99 = `176/198`
C.23/33 = `138/198`
D.39/66 = `117/198`

Answer 7

You want to find a number between \(\dfrac{8}{11} = \dfrac{72}{99}=\color{blue}{\dfrac{144}{198}}\) and \(0.\overline{85} = \dfrac{85}{10^2-1} = \dfrac{85}{99}= \color{blue}{\dfrac{170}{198}}\)

Answer 8

It would be \[\frac{ 157 }{ 198 }\] I think @ganeshie8

Answer 9

Yep!

Answer 10

oh my gosh thank you so much

Answer 11

yw:)