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Physics 16 Online
OpenStudy (amilapsn):

What is the equivalent capacitance of the following circuit?

OpenStudy (amilapsn):

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OpenStudy (anonymous):

I can help you if this website will let me. I will start you off. i have combined two caps in parallel and redrawn and labeled the circuit. The draw routine on this site is not working so I will attach a diagram I have labeled the nodes a...e. i have labeled the charges on each side of the caps I note that the charge on the three caps connect to "a" have a total charge equal Q1+Q2+Q3 which must equal to the total charge on the caps connected to "e" -(Q6+Q4-Q3) WHY? I note that the sum of the charges on the plates of caps at nodes b,c,d must sum to zero. WHY? You are looking for an equivalent cap to replace your circuit. For any cap CV =Q. Thus for your equiv cap C eq,= (q1+q2+q3)/Vo. You can write additional voltage loop equations for more relations between charges. You have six unknowns an at least six equations so you can solve for the charges in terms of Vo. Take it from here

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