Mathematics
9 Online
OpenStudy (anonymous):
What is a factor of 6x^2y+8x^2-30y-40
A. x-4
B. 3y+4
C. x^2+4
D. 3y-5
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OpenStudy (anonymous):
Here is another @DoShKa_SyRiA
OpenStudy (anonymous):
sorry i suck at Algebra 2 any other math I'm fine
OpenStudy (anonymous):
why is it 6x^2y?
OpenStudy (anonymous):
its 6 x squared times y
OpenStudy (anonymous):
\[6x ^{2}y\]
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OpenStudy (zale101):
Are you familiar with group factorization?
OpenStudy (anonymous):
kinda
OpenStudy (anonymous):
2(x2−5)(3y+4)
OpenStudy (anonymous):
B.
OpenStudy (anonymous):
factor the GCF, group the terms, factor GCF from each group, factor the common binomial, and check your work
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OpenStudy (anonymous):
2(x^2-5)(3y+4)
OpenStudy (zale101):
\((6x^2y+8x^2)-(30y+40)\)
In each parenthesis factor out the common factor.
\(x^2(6y+8)-5(6y+8)\)
OpenStudy (anonymous):
B.(3y+4)
OpenStudy (anonymous):
i thought it was b
OpenStudy (zale101):
x^2 was common in the first parenthesis
5 was also common in the second parenthesis
so i factored them out
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OpenStudy (anonymous):
but i think i messed up when i checked it
OpenStudy (anonymous):
ok i can solve it from there @Zale101
OpenStudy (anonymous):
thx all
OpenStudy (zale101):
Yes
OpenStudy (zale101):
Factor out the common factor which is (6y+8)
\(x^2(6y+8)−5(6y+8)\)
\((x^2-5)(6y+8)\)
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OpenStudy (zale101):
then keep factoring out from there^
OpenStudy (zale101):
and see if you get something that fits your choices