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Mathematics 20 Online
OpenStudy (anonymous):

What is a factor of 6x^2y+8x^2-30y-40 A. x-4 B. 3y+4 C. x^2+4 D. 3y-5

OpenStudy (anonymous):

Here is another @DoShKa_SyRiA

OpenStudy (anonymous):

sorry i suck at Algebra 2 any other math I'm fine

OpenStudy (anonymous):

why is it 6x^2y?

OpenStudy (anonymous):

its 6 x squared times y

OpenStudy (anonymous):

\[6x ^{2}y\]

OpenStudy (zale101):

Are you familiar with group factorization?

OpenStudy (anonymous):

kinda

OpenStudy (anonymous):

2(x2−5)(3y+4)

OpenStudy (anonymous):

B.

OpenStudy (anonymous):

factor the GCF, group the terms, factor GCF from each group, factor the common binomial, and check your work

OpenStudy (anonymous):

2(x^2-5)(3y+4)

OpenStudy (zale101):

\((6x^2y+8x^2)-(30y+40)\) In each parenthesis factor out the common factor. \(x^2(6y+8)-5(6y+8)\)

OpenStudy (anonymous):

B.(3y+4)

OpenStudy (anonymous):

i thought it was b

OpenStudy (zale101):

x^2 was common in the first parenthesis 5 was also common in the second parenthesis so i factored them out

OpenStudy (anonymous):

but i think i messed up when i checked it

OpenStudy (anonymous):

ok i can solve it from there @Zale101

OpenStudy (anonymous):

thx all

OpenStudy (zale101):

Yes

OpenStudy (zale101):

Factor out the common factor which is (6y+8) \(x^2(6y+8)−5(6y+8)\) \((x^2-5)(6y+8)\)

OpenStudy (zale101):

then keep factoring out from there^

OpenStudy (zale101):

and see if you get something that fits your choices

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