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OpenStudy (aaronandyson):
@robtobey
OpenStudy (aaronandyson):
@robtobey
@ParthKohli
@eta
Parth (parthkohli):
Obtain the value of tan(theta) by dividing both sides by cos(theta).
Then construct a triangle and find the values of sin(theta), cos(theta), cot(theta) and cosec(theta).
OpenStudy (aaronandyson):
So what
4 tan (theta) = 2(theta)
@ParthKohli
Parth (parthkohli):
Huh...
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OpenStudy (aaronandyson):
?
OpenStudy (aaronandyson):
sorry
4 tan (theta) = 3(theta)
@ParthKohli
Parth (parthkohli):
No... show your work.
OpenStudy (aaronandyson):
sin/cos = tan
cos/cos = 1
so
4 sin/cos = 2 cos/cos
OpenStudy (aaronandyson):
ugh
4 sin/cos = 3 cos/cos
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Parth (parthkohli):
2 sin theta = 3 cos theta
how did you get the 4?
OpenStudy (aaronandyson):
My keyboard is lagging its suppose to be
4 sin theta and not 2
sorry for the error.
OpenStudy (aaronandyson):
So what next @ParthKohli
OpenStudy (aaronandyson):
@ParthKohli
OpenStudy (aaronandyson):
@ParthKohli
@robtobey
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OpenStudy (aaronandyson):
@ribhu
Parth (parthkohli):
Oh, OK. That makes things simpler.
Parth (parthkohli):
Use the identity \(\sin\theta/\cos \theta = \tan \theta.\)
OpenStudy (aaronandyson):
I did and I got
tan = 3/4
OpenStudy (aaronandyson):
@ParthKohli
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Parth (parthkohli):
Now make a triangle with opposite = 3 units and adjacent = 4 units.
OpenStudy (aaronandyson):
Sorry but it's 4 sin theta and not two
OpenStudy (aaronandyson):
|dw:1425150890636:dw|
OpenStudy (aaronandyson):
@ParthKohli
OpenStudy (aaronandyson):
@ParthKohli
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OpenStudy (aaronandyson):
@ribhu
OpenStudy (aaronandyson):
@ParthKohli
OpenStudy (aaronandyson):
sin = 3/5
cos = 4/5
right?
Parth (parthkohli):
well done
OpenStudy (aaronandyson):
Now?
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