can someone help me with this one please 16x^4+54x^2-7

Question

irishboy123 · Answer

1/8, -7/2

anonymous · Answer

How did you get that?

irishboy123 · Answer

you didn't actually specify what you wanted doing with the equations!  

if you want stationary points or intercepts or whatever, you should spell that out.

the numbers I gave solve 16y^2+54y-7 = 0 --- you should notice that i subbed y for x^2 and solved for **y**.

THUS if you are trying to find the roots of the original question based in x, the roots are the sqrts of these numbers, and they number 4 because you gave a quartic.

however, it could be that you are integrating the original equation or finding a volume of revolution or an arc length.  

hope this helps.

directrix · Answer

Are you looking for the solutions to this equation:  16x^4+54x^2-7=0

@Crazy.c.246

directrix · Answer

If so, factor:

16x^4+54x^2-7=0

(2x^2 + 7) * (8x^2 - 1) = 0