Question

I WILL GIVE A MEDAL!!!
Divide: (x+2/2x)/(6/x+3)
Discuss why the degree of the resulting denominator did not change from your expression’s degree.

Answer 1

\[\huge \frac{ x+\frac{ 2 }{ 2x } }{ \frac{ 6 }{ x+3 } }\] is this your problem?

Answer 2

choice A
\[\frac{x+\frac{2}{2x} }{\frac{6}{x}+3}\]
choice B
\[\frac{\frac{x+2}{2x} }{\frac{6}{x}+3}\]
choice C
\[\frac{\frac{x+2}{2x} }{\frac{6}{x+3}}\]

Answer 3

choice C

Answer 4

\[\huge \frac{\frac{x+2}{2x} }{\frac{6}{x+3}}\] ok cool, so have you tried anything yet?

Answer 5

Nope I am lost

Answer 6

Which part are you confused with?

Answer 7

The whole thing. I'm not that good with dividing these things.

Answer 8

\[\huge \frac{ \frac{ a }{ b } }{ \frac{ c }{ d } } \implies \frac{ a }{ b } \times \frac{ d }{ c }\]

Answer 9

okay so I would put it as this: