I got a number bigger then all of the answers below and was hoping some one could explain how to do it.
A car dealer has 7 new sedans she wants to display but room for only 5 on the showroom floor.How many ways can she display the 7 cars on the showroom floor?

A.5040
B.2520
C.21
D.35

Question

I got a number bigger then all of the answers below and was hoping some one could explain how to do it.
 A car dealer has 7 new sedans she wants to display but room for only 5 on the showroom floor.How many ways can she display the 7 cars on the showroom floor?

A.5040
B.2520
C.21
D.35

anonymous · Answer

35 :)

anonymous · Answer

Oh, thank you i feel so well lets just say not exactly bright at this moment for not getting that.

anonymous · Answer

lol np fan and medal

anonymous · Answer

Sorry, can't fan u already did.

anonymous · Answer

lol

fibonaccichick666 · Answer

@IQ250 please remember that we are to assist the asker in achieving an answer-not just give them it. Please check out the code of conduct here http://openstudy.com/code-of-conduct

anonymous · Answer

lol

noelgreco · Answer

The question asks how many different ways can the cars be displayed, that means order counts, and it's a permutation calculation - definitely NOT 35. 
$$_{7}P _{5}$$