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OpenStudy (anonymous):
Use the identities to find the exact value of the following.
tan(theta)=-7/2; on (pi/(3pi/2)); sec(theta)
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OpenStudy (freckles):
I guess you mean (pi,3pi/2)
OpenStudy (freckles):
which is the third quadrant
where both cos and sin are negative
OpenStudy (freckles):
and if cos is neg then sec is neg
OpenStudy (freckles):
since they are reciprocal functions
OpenStudy (freckles):
anyways recall the pythagorean identity
\[1+\tan^2(\theta)=\sec^2(\theta)\]
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OpenStudy (freckles):
Plug in what you got for tan(theta) and solve for sec(theta)
OpenStudy (freckles):
by the way your tan makes no sense for that quadrant
OpenStudy (freckles):
since tan is suppose to be positive in the 3rd quadrant
OpenStudy (anonymous):
Well my teacher isn't the brightest to be honest. She doesn't teach and she only knows how to flip through a PowerPoint.
OpenStudy (freckles):
we can still do the problem
even though some of it doesn't make sense though
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OpenStudy (freckles):
because we will squaring tan anyways
OpenStudy (anonymous):
I think I have it but thanks you for the help
OpenStudy (freckles):
well what you get
OpenStudy (anonymous):
Sec(theta) = -sqrt53/4
OpenStudy (freckles):
yeah you mean -sqrt(53/4) or -sqrt(53)/2 :)
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