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Mathematics 21 Online
OpenStudy (anonymous):

Use the identities to find the exact value of the following. tan(theta)=-7/2; on (pi/(3pi/2)); sec(theta)

OpenStudy (freckles):

I guess you mean (pi,3pi/2)

OpenStudy (freckles):

which is the third quadrant where both cos and sin are negative

OpenStudy (freckles):

and if cos is neg then sec is neg

OpenStudy (freckles):

since they are reciprocal functions

OpenStudy (freckles):

anyways recall the pythagorean identity \[1+\tan^2(\theta)=\sec^2(\theta)\]

OpenStudy (freckles):

Plug in what you got for tan(theta) and solve for sec(theta)

OpenStudy (freckles):

by the way your tan makes no sense for that quadrant

OpenStudy (freckles):

since tan is suppose to be positive in the 3rd quadrant

OpenStudy (anonymous):

Well my teacher isn't the brightest to be honest. She doesn't teach and she only knows how to flip through a PowerPoint.

OpenStudy (freckles):

we can still do the problem even though some of it doesn't make sense though

OpenStudy (freckles):

because we will squaring tan anyways

OpenStudy (anonymous):

I think I have it but thanks you for the help

OpenStudy (freckles):

well what you get

OpenStudy (anonymous):

Sec(theta) = -sqrt53/4

OpenStudy (freckles):

yeah you mean -sqrt(53/4) or -sqrt(53)/2 :)

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