Use the identities to find the exact value of the following. tan(theta)=-7/2; on (pi/(3pi/2)); sec(theta)
I guess you mean (pi,3pi/2)
which is the third quadrant where both cos and sin are negative
and if cos is neg then sec is neg
since they are reciprocal functions
anyways recall the pythagorean identity \[1+\tan^2(\theta)=\sec^2(\theta)\]
Plug in what you got for tan(theta) and solve for sec(theta)
by the way your tan makes no sense for that quadrant
since tan is suppose to be positive in the 3rd quadrant
Well my teacher isn't the brightest to be honest. She doesn't teach and she only knows how to flip through a PowerPoint.
we can still do the problem even though some of it doesn't make sense though
because we will squaring tan anyways
I think I have it but thanks you for the help
well what you get
Sec(theta) = -sqrt53/4
yeah you mean -sqrt(53/4) or -sqrt(53)/2 :)
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