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Write the expression in terms of sin and cosine and express the result in simplest form. (Step by step with distribution please.) ( I get lost while distributing "sec θ" to 1 and "cot θ") sec θ (1 + cot θ) - csc θ (1 + tan θ)
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This is where I get lost after distributing \[\frac{ 1 }{ \cos0 } \] to 1
\[\frac{1}{a}(1+a)-\frac{1}{b}(1+\frac{b}{a})\]
you get \[\frac{1}{a}+1-\frac{1}{b}-\frac{1}{a}\]after distributing
that leaves \[1-\frac{1}{b}\]
or \[1-\frac{1}{\sin(x)}\] or even \[1-\csc(x)\] if you prefer
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what are a and b
\[a=\cos(x), b=\sin(x)\] is is 100% algebra, easier to write with \(a,b\) instead of sine and cosine
oh thanks
\[\color\magenta\heartsuit\]
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