: If both cylinder heads are free to move, what weight would we have to put on the large cylinder head to keep it from moving (assume that the weight of the large cylinder head is negligible)?

Question

anonymous · Answer

already figured out the answer to 2: It wont move. Use the diagram for question above

irishboy123 · Answer

the principle here is that static pressure is transferred through an incompressible fluid so the static pressure at each cylinder head will be the same.  and pressure is measured as force/area.

hence F1/A1 = F2/A2.

you therefore need to know the respective x-section areas at each cylinder head.

the question you ask does not suggest that there is any force on the small end so i do not understand what needs to be calculated.

anonymous · Answer

it was from the previous question...but thanks you helped lots