Question

What is the solution to x=sqrt 3x plus 10?
3x+10 is all under the sqrt

Answer 1

\[x = \sqrt{3x + 10}\]

Answer 2

HI!!

Answer 3

Any ideas on what to do first?

Answer 4

I squared both sides and got x^2=3x+10
then took 10 from both sides and got x^2 -10=3x
now I'm lost

Answer 5

if it was me, i would guess that is what i would do first

Answer 6

there are not that many perfect squares

Answer 7

I know I need to divide the 3 but how do i get rid of the x^2

Answer 8

\[x ^{2} = 3x +10\]

Answer 9

\[\sqrt{3x+10}\] what x will make it a perfect square ?

Answer 10

not 1, 2 will but \(\sqrt{16}=4\) not \(2\)
3 doesn't work
neither does 4
how about 5?

Answer 11

\[x ^{2} - 3x + 10 = 0\]

Answer 12

got it on the fifth try

Answer 13

oh ya get it all to one side

Answer 14

Yep

Answer 15

everyone love algebra, no one wants to try experimenting
why is that?

Answer 16

but wouldn't be an negative 10

Answer 17

Do you know how to factor this? @costonla

Answer 18

Well in general when you have a ax^2+bx+c you factor it like this..

Answer 19

(x-5)(x-3)

Answer 20

(x+3)

Answer 21

\[(x - \space ) ( x + \space ) = 0\]

Answer 22

x=5 and -3 right

Answer 23

Not quite because that would result in 15 not 10.

Answer 24

scratch 3 and insert 2

Answer 25

The two last numbers multiplied together need to =10

Answer 26

\[(x-5) \space (x+2) \space = 0\]

Answer 27

if i looked at the question right when we moved the 3x +10 to the other side we should have put a negative in front of both

Answer 28

Yeah sorry I mistyped that but fixed it

Answer 29

so then x= 5 and -2

Answer 30

Correct!

Answer 31

ok thank you, I forgot to move all to one side and set to 0

Answer 32

Nw :)