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Mathematics 6 Online
OpenStudy (anonymous):

ill give you a medal.if you can Explain thoroughly What are the points of discontinuity? Are they all removable? y= (x - 5) / x^2 - 6x + 5

terenzreignz (terenzreignz):

\[\Large y = \frac{x-5}{x^2 - 6x + 5}\] Well...

OpenStudy (misty1212):

HI!!

OpenStudy (misty1212):

factor the denominator, then find out where it is zero those are the discontinuities

OpenStudy (misty1212):

then cancel that "removes" one of the discontinuities

terenzreignz (terenzreignz):

What you must understand is that this function is what's called a "rational" function, that is to say, it is a quotient of two polynomials. And rational functions are continuous EVERYWHERE ON THEIR DOMAIN. That being said, the only places there could ever be discontinuities on a rational function, are those places that are not in its domain. Can you find certain x values not in the domain? (I say domain a lot... urgh)

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