ill give you a medal.if you can Explain thoroughly What are the points of discontinuity? Are they all removable? y= (x - 5) / x^2 - 6x + 5
\[\Large y = \frac{x-5}{x^2 - 6x + 5}\] Well...
HI!!
factor the denominator, then find out where it is zero those are the discontinuities
then cancel that "removes" one of the discontinuities
What you must understand is that this function is what's called a "rational" function, that is to say, it is a quotient of two polynomials. And rational functions are continuous EVERYWHERE ON THEIR DOMAIN. That being said, the only places there could ever be discontinuities on a rational function, are those places that are not in its domain. Can you find certain x values not in the domain? (I say domain a lot... urgh)
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