Question

Help please! Medal and fan

Part A: Divide (9x4y3 + 3x3y2 - 6x2y - 12x2y4) by -3x2y. Show your work, and justify each step.

Part B: How would your answer in Part A be affected if the x2 variable in the denominator was just an x?

Part C: What is the degree and classification of the polynomial you got in Part A?

Answer 1

If you have the time i would also be grateful if you explain the answer.

Answer 2

I will help u

Answer 3

IGreen can u help her plz

Answer 4

Divide all the whole numbers by -3

Answer 5

Subtract all the exponents of 'x' by 2, and subtract all the exponents of 'y' by 1.

Answer 6

\(\dfrac{9x^4y^3 + 3x^3y^2 - 6x^2y - 12x^2y^4}{-3x^2y} \)

\(\dfrac{9x^4y^3}{-3x^2y} \rightarrow \dfrac{9}{-3} x^{4-2}y^{3-1}\)

Simplify that

Answer 7

Divide 9 / -3, subtract 4 - 2, and subtract 3 - 1

Answer 8

-3x^2^2 + -1xy + -2xy + -4xy^3

Answer 9

This is what i got

Answer 10

-3x^2y^2

Answer 11

This is correct: "-3x^2^2 + -1xy"

Answer 12

-2xy is incorrect..

Answer 13

So is -4xy^3

Answer 14

\(\dfrac{-6x^2y}{-3x^2y}\)

Answer 15

The variables cancel out because they're the same..so just divide -6 / -3, what do you get?

Answer 16

Oh i see its because the negatives cancel each other out. So -6x^2y / -3x^2y = 2xy?

Answer 17

@iGreen