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OpenStudy (solomonzelman):
first take out the 'x'
what do you get after doing so>?
OpenStudy (anonymous):
3+6-24
OpenStudy (compassionate):
Eh, what he's saying is factor x throughout the expression via LCD/M
OpenStudy (compassionate):
\[3x^3 + 6x^2 - 24x = x(3x^2 + 5x - 24)\] Now you're simply left with, on the right side, a binomial
OpenStudy (compassionate):
\[3x^2 + 6x - 24\]
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OpenStudy (anonymous):
ok.. whats the next step?
OpenStudy (compassionate):
\[x(3x^2 + 6 - 24) = x(3x \pm ?)(x \pm ?)\] You are simply solving it as if it were a binomial.
OpenStudy (anonymous):
ok. let me write it out in my note book
Nnesha (nnesha):
there is a typo \[x( 3x^2 + 6x -24)\]
suppose to be this
OpenStudy (anonymous):
._. ugh
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Nnesha (nnesha):
yep first step is to find GCF ( greatest common factor )
like they told you that x is one of common factor so basically you have to divide whole equation by x
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