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Evaluate sin 18 degrees
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using trig identities and formulas
yehp
i began with this: sin 18 = cos 72
not exact, i mean in terms of radicals
there is a way with manipulation of the trig identities
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\[2\cos ^{2}36 - 1 = \cos 72\]
\[2(1-2\sin ^{2}18)^{2}-1 = \cos 72\]
then im lost
o ok
@Rizags Are you familiar with the trigonometric products, example: \(\rm sin^2(x)=(1-cos(2x))/2\) If you apply it twice, you get the above identity, after which you can solve for sin(18)=cos(72)
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so input x=36?
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