Question

What are the zeroes of f(x) = x2 - 6x + 8? (4 points)

x = -4, 2
x = -4, -2
x = 4, 2
x = 4, -2

Answer 1

you can use quadratic formula or
you can find the factors of the coefficients of the leading term and the last term.

Answer 2

$$
f(x)=x^2-6x+8=(x-2)(x-4)
$$
When is
$$
f(x)=0
$$
That is, when is x-2 =0 and x-4 = 0?

Answer 3

the substitute those values into the equation, until you get zero

Answer 4

B?