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The quarterback on a football team completes 70% of his passes. He attempts three passes (assumed to be independent) in a given quarter. a. What is the probability that he will not complete any passes? b. What is the probability that he will complete exactly 2 passes?
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Let p = probability of completion Let q = probability of non completion $$ \large q=1-p $$ a. No completions in three attempts is $$ \large q^3 $$ b. He can complete 2 passes in three ways: $$ ppq+qpp+pqp $$ Right?
Ok with you so far.
Will it be a percentage when I get the answer?
No. Question asks for probability. Percentage is the answer when they ask for the chance of something. Substitute p=0.7 and q=0.3 to get your answers.
a) 0.027 b) 0.441
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