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y=√4x-13 find the domain can somebody explain step by step please
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how far does the square root extend? is it \(\Large y = \sqrt{4x-13}\) ?? OR is it \(\Large y = \sqrt{4x}-13\) ??
the first one
You cannot have the terms under the square root be negative, so we have to force 4x-13 to be 0 or positive which means you need to solve this for x \[\Large 4x - 13 \ge 0\]
what do you get when you do so?
\[4x \ge 13\]
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you can then divide both sides by 4 to get \[\Large x \ge \frac{13}{4}\]
so the domain is the set of all real numbers x such that \(\Large x \ge \frac{13}{4}\)
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