For y = 4x + 2x2 – x3, show how to find the value for y, when x = 2. Show your work
Can you clarify the question, please? When reading the problem, there is a few errors. Did you mean --\[y=4x+2x^2-x^3\] the way you have it written, it looks like y=4x+ (2*2)-x(3).
yes i did
@iGreen, I think you'd be better at helping her than I would.
\(4(2) + 2(2)^2 – (2)^3\) Simplify
okay
What's 4 * 2
that would be 8
so 2(2) which = 2*2 would equal to 4 right
Sari, For every x you see in the problem, replace it with the number 2. so its going to look like this \[4(2)+2(2)^2-2^3\] so, you should be able to go from there.
okay
Sari, 4(2) just means Four times two. so. 4(2)= 8 2(2)^2 is equal to 8 aswell, and so is 2^3. so, youre left with 8+8-8. I think you can handle that.
yes thanks
8+8-8=8 correct
Yes. You got it :p
so what's the aswer 8
i mean y=8
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You are correct :)
thank you
Your'e Welcome
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