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Mathematics 10 Online
OpenStudy (anonymous):

Evaluate. 5/6 + 1/3 · 5/8 Write your answer in simplest form.

OpenStudy (anonymous):

hello XD

OpenStudy (anonymous):

ok so you can start by saying 1/3 is equivalent to 2/6

OpenStudy (anonymous):

you wana find a common what

OpenStudy (anonymous):

what would you find

OpenStudy (anonymous):

your going to have to help with this too no one can go any farther until u reply with what the bottom number is

OpenStudy (anonymous):

common denominator ...

OpenStudy (anonymous):

would be 24 XD

OpenStudy (anonymous):

soooo 20/24 +8/24 + 15/24

OpenStudy (anonymous):

wait 8/24 x 15/24

OpenStudy (anonymous):

now you solve

OpenStudy (anonymous):

i cant give answers or help you any farther do to the terms and rules you have to agree with

OpenStudy (anonymous):

sorry I've been trying to reply my computer is soooooo slow lol

OpenStudy (anonymous):

XD it ok

OpenStudy (anonymous):

remember pemdas btw

OpenStudy (anonymous):

so now do I just multiply 8 with 15 ? sorry I'm really bad at math

OpenStudy (anonymous):

parenthesis exponents multiplication division addition subtraction

OpenStudy (anonymous):

pemdas and that is the order of solving problems

OpenStudy (anonymous):

multiply them

OpenStudy (anonymous):

as fractions

OpenStudy (youngsuperman):

yall keepp anwser before i do dang i feel bad

OpenStudy (anonymous):

To multiply fractions: Simplify the fractions if not in lowest terms. Multiply the numerators of the fractions to get the new numerator. Multiply the denominators of the fractions to get the new denominator.

OpenStudy (anonymous):

i got 48/ 360 i think I'm wrong lol …….

OpenStudy (anonymous):

5/24 + 20/24

OpenStudy (anonymous):

1 1/24 i believe

OpenStudy (anonymous):

am i correct on this @iGreen

OpenStudy (anonymous):

oh well i gtg should be 1 1/24 i think

OpenStudy (anonymous):

@xo.minnie.xox try dis for me plz see if im right

OpenStudy (anonymous):

@iGreen i need yo help

OpenStudy (anonymous):

gg gtg

OpenStudy (anonymous):

ok thanks for helping

OpenStudy (anonymous):

you were correct

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