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What is the equation of the line passing through the point (-4, -5) and having a slope of 4?
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y=4x+21
y=4x-21
y=4x+11
y=4x-11
@iGreen
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y=4x+11 goes up 4
y=4x+21 goes up 4 too
Plug those into Point-Slope form. \(y - y_1 = m(x - x_1)\) Where \(y_1\) is the y-value of the point, \(x_1\) is the x-value of the point, and \(m\) is the slope. So we have: \(y + 5 = 4(x + 4)\) Distribute 4 into the parenthesis: \(y + 5 = 4x + 16\) Subtract 5 to both sides, what's 16 - 5?
11
y=4x+11?
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Yep, you got it.
thx
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