Find the first six terms of the sequence. (1 point)

a1 = 6, an = 2 • an-1
(A) 12, 24, 48, 96, 192, 384
(B) 6, 12, 14, 16, 18, 20
(C) 0, 2, 12, 14, 16, 18
(D) 6, 12, 24, 48, 96, 192

Question

Find the first six terms of the sequence. (1 point) 

a1 = 6, an = 2 • an-1
(A)	12, 24, 48, 96, 192, 384
(B)	6, 12, 14, 16, 18, 20
(C)	0, 2, 12, 14, 16, 18
(D)	6, 12, 24, 48, 96, 192

anonymous · Answer

You're given the first term, seems you just have to plug in other terms into your formula you're given.

anonymous · Answer

How can I set that up? Take me through  the first one as an example @iambatman

anonymous · Answer

First, tell me what your first term is, then we can eliminate two of the choices.

anonymous · Answer

That's literally the entire question word for word, there isn't anything else @iambatman

anonymous · Answer

I'm asking you for the first term.

anonymous · Answer

What is it, it's given.

anonymous · Answer

6?

anonymous · Answer

Yes, that's what a1 means, and I'm assuming your problem is actually $$a_n=2 \times a_n-1$$

anonymous · Answer

yes @iambatman

anonymous · Answer

Ok so plug in the value 2, since we're looking for a_2

anonymous · Answer

That will give you a_2 = 2*a1 => a_2 = 2*6 = 12

anonymous · Answer

Do the same with the rest of them

anonymous · Answer

oh okay thank you @iambatman