Solve the equation. If necessary, round your answer to the nearest tenth.
9x2 = 49
2.3, –2.3
5.4, –5.4
7, –7
21, –21
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OpenStudy (juliebeans):
@sammixboo
OpenStudy (mathstudent55):
First, subtract 49 from both sides.
What do you get?
OpenStudy (juliebeans):
erhm 1,5.4
OpenStudy (mathstudent55):
\(9x^2 = 49\)
Start by subtracting 49 from both sides:
\(9x^2 - 49 = 0\)
OpenStudy (juliebeans):
ok
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OpenStudy (mathstudent55):
Now factor the left side.
The left side is a difference of squares.
Do you know how to factor a difference of squares?
It follows this pattern:
\(a^2 - b^2 = (a + b)(a - b) \)
OpenStudy (mathstudent55):
You have \(9x^2 - 49\)
\(9x^2\) is the square of 3x.
49 is the square of 7.
You can rewrite \(9x^2 - 49\) as \((3x)^2 - 7^2\) which clearly shows the two squares.
OpenStudy (mathstudent55):
Now you factor the left side using the pattern I showed above.
OpenStudy (juliebeans):
Can we combine the 9x2 and 3x(2) togther?
OpenStudy (juliebeans):
@mathstudent55
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OpenStudy (mathstudent55):
No.
I'll show you with a drawing to make it easier to see how a difference of squares factors.