A right triangle has base (x - 7) units and height (2x - 10) units.

Part A: What is the square of the length of the hypotenuse of the triangle? Show your work. (4 points)

Part B: What is the area of the triangle? (3 points)

Part C: Using the solution obtained in Part B, explain the closure property of multiplication of polynomials. (3 points)

Question

A right triangle has base (x - 7) units and height (2x - 10) units.

Part A: What is the square of the length of the hypotenuse of the triangle? Show your work. (4 points)

Part B: What is the area of the triangle? (3 points)

Part C: Using the solution obtained in Part B, explain the closure property of multiplication of polynomials. (3 points)

anonymous · Answer

@TrojanPoem

trojanpoem · Answer

hypo = k
k^2 = (x-7)^2 + (2x -10)^
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anonymous · Answer

So I have to find the other side, How do I do that ?
I wrote exactly that down on paper but couldn't figure how to get what AB is

trojanpoem · Answer

No  clue. I got 2 variables in one equation impossible to be solved.

anonymous · Answer

Alright, can you help me find the area ?

trojanpoem · Answer

yep Area = 0.5 * base * height

anonymous · Answer

How exactly do I multiply x - 7 and 2x - 10

trojanpoem · Answer

(x-7)(2x-10)
x times 2x, -10 then -7 times 2x , -10

anonymous · Answer

Uh
I have no idea was x times 2x is

anonymous · Answer

-10 x -7 = 70

trojanpoem · Answer

2x * x = 2x^2