Question

Quadrilateral EFGH has coordinates E(a, 2a), F(3a, a), G(2a, 0), and H(0, 0). Find the midpoint of HG.

(2a, 0)
(a, 2a)
(a, a)
(a, 0)

Answer 1

@conner143

Answer 2

ok ill try

Answer 3

midpoint = \((\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2})\)

Answer 4

what does a=

Answer 5

it doesn't have to equal anything. it's a variable. if it helps you can set it to some arbitrary number

Answer 6

a is just in place of a variable :)

Answer 7

oh ok

Answer 8

and so the midpoint of HG would be where H=(x1,y1) and G is (x2,y2)
then you can plug it in

Answer 9

do you want the answer or help finding it out?

Answer 10

Both would be great! :)

Answer 11

ok so the answer is (a,0)

Answer 12

i got it bc you use the midpoint formula. so you do this
2a-0 0-0
----- , ----
2 2

and when you get the answers you put them together like coordinates so 2a-0 is 2a and 2a/2 would be a so x=a
and you would do 0-0 which is 0 so 0/2 is o so y=0
so therefor the answer is (a,0)
does that make since @alohakaika

Answer 13

Yes! :) Thanks @conner143

Answer 14

ok no problem anytime just ask