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Chris wrapped a present with the following dimensions: a length of 5 in, a width of 4 in and a height of 6 in. Henry wrapped a present that had a height that was double Chris' present's height. How much more wrapping paper will Henry need than Chris? A. 108 sq in B. 148 sq in C. 256 sq in D. 404 sq in
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@myronnapora
@Godlovesme
well its pretty simple u just evry number
just double every number
and the formula is lenght times width times hight = surface area
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@partyrainbow276
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