Question

Chris wrapped a present with the following dimensions: a length of 5 in, a width of 4 in and a height of 6 in. Henry wrapped a present that had a height that was double Chris' present's height. How much more wrapping paper will Henry need than Chris?
A. 108 sq in
B. 148 sq in
C. 256 sq in
D. 404 sq in

Answer 1

@myronnapora

Answer 2

@Godlovesme

Answer 3

well its pretty simple u just evry number

Answer 4

just double every number

Answer 5

and the formula is lenght times width times hight = surface area

Answer 6

@partyrainbow276