Question

Six less than the product of two consecutive positive integers is equal to six times their sum. Find the two integers please help

Answer 1

HI!!

Answer 2

solve \\[n(n+1)-6=6(n+n+1)\]

Answer 3

so it'll be n^2+n-6=6n+6n+6??/

Answer 4

Correct. The first positive integer will be equal to n, and the second positive integer will be n + 1

Answer 5

so do i have to factor it out, to get the answer for the first integer?