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OpenStudy (anonymous):
Six less than the product of two consecutive positive integers is equal to six times their sum. Find the two integers please help
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OpenStudy (misty1212):
HI!!
OpenStudy (misty1212):
solve \\[n(n+1)-6=6(n+n+1)\]
OpenStudy (anonymous):
so it'll be n^2+n-6=6n+6n+6??/
OpenStudy (anonymous):
Correct. The first positive integer will be equal to n, and the second positive integer will be n + 1
OpenStudy (anonymous):
so do i have to factor it out, to get the answer for the first integer?
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