Question

Comments!

Answer 1

WYF!

Answer 2

3,4, 2, 1, 5

Answer 3

I'd say you need to find the area of the cross sections...

and place them in order from smallest area to largest area...

if all the points are equidistant

7, 4
16, 19

this cross section is 2 units long and 1 unit wide... so has a cross section area of 2 units^2

the cross section area 8, 3, 11, 12 needs pythagoras for find the length between 8 and 12.... the triangle has shorter sides 2 and 1

this method is also needed for 5, 6, 13, 14... use pythagoras to find the length between 6 and 13...sides 3 and 2

the last option 2, 5, 18, 13 also needs pythagoras sides 1 and 2.

hope it helps

Answer 4

your solution looks correct to me