Out of 8 different consonants and 3 different vowels, how many “words” (including
nonsense words) of 3 consonants and 2 vowels can be formed if letters may not be
repeated?

Question

Out of 8 different consonants and 3 different vowels, how many “words” (including
nonsense words) of 3 consonants and 2 vowels can be formed if letters may not be
repeated?

thomas5267 · Answer

Are you familiar with the choose function?

lncognlto · Answer

I don't really understand how it works. Like, I get if you have eleven letters and you want five, you have 11C5 possible combinations. However, when it gets more complicated, I'm not sure.

thomas5267 · Answer

The are 8C3 ways to choose the consonants and there are 3C2 ways to choose the vowels, how many ways are there to choose the consonants and the vowels combined?

lncognlto · Answer

I would say (8C3)(3C2) ways?
I'm sorry for the silly questions, I'm sleep deprived as hell right now. .-.

thomas5267 · Answer

How many ways are there to arrange 5 letters then?

lncognlto · Answer

There would be 5! ways of arranging them

lncognlto · Answer

So there would be a total of (8C3)(3C2)(5!) ways?

thomas5267 · Answer

Yes I think so.  @ganeshie8 Is that correct?

ganeshie8 · Answer

that looks good to me !

ganeshie8 · Answer

maybe we can doublecheck by working it in another way