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Factor completely. If the polynomial is not factorable, write prime. 18. 3a^2bx + 15cx^2y + 25ad^3y
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in the first one, there are just two terms to consider 6a^2b^2 + 18ab^3 both terms have a factor of 6...so factor it out as 6(a^2b^2 + 3ab^3) now both terms have a's...an a^2 and the 2nd term has just an a...so you can only factor out an a 6a(ab^2 + 3b^3) now we can look at the b's the first term has a b^2 and the 2nd term has a b^3...so we can pull out at least 2 factors of b, or a b^2 6ab^2(a + 3b)
\[3a^2bx+23ad^3y+15cx^2+y\] try this.
@YesThisIsDog I need help on the polynomial that I posted
what do you need? @Firejay5
go to question this one is closed
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