Factor completely. If the polynomial is not factorable, write prime. 18.) 3a^2bx + 15cx^2y + 25ad^3y
\[3a^2bx + 15cx^2y + 25ad^3y\]
@ganeshie8 @iGreen @paki
does one of your answers begin with 25?
just read answer my question and DON'T type the question into Goggle cause the problems to the question aren't the same @DivineSolar
I am not firejay :)! I think it is prime because you can only really simplify the problem factoring just changes the equation to, 25ad^3y + 3a^2bx + 15cx^2y
So in all it does not factor leaving it prime.
I say it's prime, because 25 doesn't go into 3 evenly, but 15 does.
Why i agree with that though :).
Considering the fact you can't even factor it. It is prime.
Nope all of them have to factor with the major one and in this case it's 3
http://www.wolframalpha.com/input/?i=factor+3a%5E2b*x+%2B+15cx%5E2y+%2B+25ad%5E3y
Haha using an online calculator to do it :). And that proves my point. It can't be factored ;)
I never said @ganeshie8 OR @DivineSolar that you were wrong, it's the fact that 15 and 25 both don't go into 3 evenly to factor it out
I understand that ^-^! Anyways good luck with the rest of your quiz/test/assignment that you are doing that involves this question.
What I was saying was there was no point in putting it in Wolfram Alpha or ignoring what was saying about the 3, 15, and 25 can't go into each other. *Note multiplying 3 * 25 to get 75 won't work, because the factor tree of 75 doesn't have any number that can be added to equal 15 in the middle.*
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