Question

Graph the function. Identify the axis of symmetry and the vertex

f(x)=x^2-4x+9

Answer 1

y=x^2-4x+9
y=(x^2-4x+4)+5
y=(x-2)^2+5
then vertex is (2,5)
and axis of symmetry is x=2

Answer 2

thanks and thank you for explaining how to get the answer.

Answer 3

a simple way for finding x of vertex is it to use this formula x=-b/2a
x=4/2=2
then put 2 in the function to find the y of vertex
f(2)=4-8+9=5
so vertex is (2,5)
and axis of symmetry is x=-b/2a