Question

Write the standard form of the line that passes through the given points. (6, 1) and (5, 4)

Answer 1

@Love_Ranaa

Answer 2

Alright so first things first, let's find the slope. Slope of a line is
\[m=y _{2}-y _{1}/x _{2}-x _{1}\]
6 and 5 are x's and 1 and 4 are y's. We need to keep them in order, so we'll do
\[m=4-1/5-6\]
\[m=-3/1=-3\]
So the slope is -3

Answer 3

But I need the standard form

Answer 4

I know I'm getting to that

Answer 5

So find the y-intercept with the slope. We have y=-3x+b
use a point to plug in for the x and y
\[(1)=-3(6)+b\]
-3*6 is -18, so we have
1=-18+b
+18 to both sides, and we have 19=b

The y-intercept is (0,19)
\[y=-3x+19\]
Now we have the slope-intercept form, we can turn it into the standard form.

Answer 6

So the standard form is
\[Ax+By=C\]
we want to isolate the c, so we'll do +3x to both sides.
\[y+3x=-3x+3x+19\]
This now becomes
\[y+3x=19\]
or
\[3x+y=19\]

So do you understand how to get it?

Answer 7

No lol

Answer 8

What do you not get